Looking it up in the back of a statistics text in a table for "distribution of t probability," you need to realize that 1 - .9 = .1.
Try .1 with n-1 or 21 df.
What critical t value would be needed to construct a 90% confidence interval on a sample of size 22?
1.717
1.323
2.080
1.321
1.721
2 answers
2.080