Asked by Daniella
Water flowing into a hemispherical tank of 5m radius at a rate of ((3m^3)/(hr))
Determine the rate at which the depth of water increases.
Determine the rate at which the depth of water increases.
Answers
Answered by
Steve
The volume of a spherical cap of height y on a sphere of radius 5 is
v = 1/3 pi y^2 (15-y)
dv/dt = pi y(10-y) dy/dt
3 = pi y(10-y) dy/dt
Since you haven't specified depth of the water when determining the measurement, this is as far as we can go for now.
v = 1/3 pi y^2 (15-y)
dv/dt = pi y(10-y) dy/dt
3 = pi y(10-y) dy/dt
Since you haven't specified depth of the water when determining the measurement, this is as far as we can go for now.
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