Asked by Aonymous
ln(e) = ln(√(2)/x) -ln(e)
Answers
Answered by
Damon
2 ln e = ln e^2
so
ln e^2 = ln (sqrt 2 / x)
e^2 = sqrt 2/x
x = sqrt 2 / e^2
so
ln e^2 = ln (sqrt 2 / x)
e^2 = sqrt 2/x
x = sqrt 2 / e^2
Answered by
Reiny
ln e = 1 , so your equation becomes
1 = ln(√(2/x) - 1
2 = ln √(2/x)
√(2/x) = e^2
square both sides
2/x = e^4
x = 2/e^4
notice how I read your expression
If you meant
ln e = ln (√2 /x) - ln 2
2 = ln (√2/x)
√2/x = e^2
x = √2/e^2
1 = ln(√(2/x) - 1
2 = ln √(2/x)
√(2/x) = e^2
square both sides
2/x = e^4
x = 2/e^4
notice how I read your expression
If you meant
ln e = ln (√2 /x) - ln 2
2 = ln (√2/x)
√2/x = e^2
x = √2/e^2
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