Asked by Doris
s(t) = 68 − 20 log (t + 14), t ¡Ý 0. a) what was the average score when they initially took the test, t = 14?
Answers
Answered by
Damon
when t = 0
log 14 = 1.15
s = 68 - 20 (1.15) = 45
when t = 14
log 28 = 1.45
s = 68 - 20(1.45) = 39
log 14 = 1.15
s = 68 - 20 (1.15) = 45
when t = 14
log 28 = 1.45
s = 68 - 20(1.45) = 39
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