Asked by James
How would I do this one?
n=1 to infinity n^n/4^1+3*n
Does it absolutely converge, conditionally converge, or diverge?
What would I do here?
n=1 to infinity n^n/4^1+3*n
Does it absolutely converge, conditionally converge, or diverge?
What would I do here?
Answers
Answered by
Damon
n^n /[ 4^(1+3n) ] or what?
Need parentheses to see what you mean.
By the way that clearly does not converge.
Need parentheses to see what you mean.
By the way that clearly does not converge.
Answered by
James
This is how it looks: hopefully this clarifies it a bit.
n^n/(4)^1+3*n
n^n/(4)^1+3*n
Answered by
Damon
but 4^1 is just 4
do you mean
n^n / (4 + 3n) ?
that would be for large n
n^n /3n
(1/3) n^(n-1)
which gets very large indeed
do you mean
n^n / (4 + 3n) ?
that would be for large n
n^n /3n
(1/3) n^(n-1)
which gets very large indeed
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