n^n /[ 4^(1+3n) ] or what?
Need parentheses to see what you mean.
By the way that clearly does not converge.
How would I do this one?
n=1 to infinity n^n/4^1+3*n
Does it absolutely converge, conditionally converge, or diverge?
What would I do here?
3 answers
This is how it looks: hopefully this clarifies it a bit.
n^n/(4)^1+3*n
n^n/(4)^1+3*n
but 4^1 is just 4
do you mean
n^n / (4 + 3n) ?
that would be for large n
n^n /3n
(1/3) n^(n-1)
which gets very large indeed
do you mean
n^n / (4 + 3n) ?
that would be for large n
n^n /3n
(1/3) n^(n-1)
which gets very large indeed
3 answers