If the solutions are p and q, then the equation must factor like:
A(x-p)(x-q) = 0
So, if you keep p and q the same, the quadratic can only differ in the overall factor A. But the equation is then the same, because:
A(x-p)(x-q) = 0 --->
(x-p)(x-q) = 0
Is it possible to have different quadratic equations with the same solution? Explain.
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