find the equation of the tangent line to f(x)=square root x passing through (-4,0)

Answer 1

y = √x = x^(1/2)
dy/dx = (1/2)x^(-1/2) = 1/(2√x)

so at (-4,0), dy/dx = 1/2√-4 ----> undefined in the real numbers
uh uh!!

look at y = √x, the point (-4,0) does not lie on your curve, so ...... bogus question

check your typing