Dry air (0% humidity) is approximately 78% N2, 21% O2, and 1% Ar by moles. Calculate the molar mass and density of dry air at 0 °C and 1.0 atm. Assume ideal behavior and use two significant figures in your answers.
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I calculated the molar mass to be approximately 29 g/mol. Although I am not entirely sure whether that is the correct answer or not.
29 is about right but I can't say you did it right since you didn't show your work.
The density = 29/22.4 = ? g/L
The density = 29/22.4 = ? g/L
28.02g N2
32.00 g O2
39.95 g Ar
Using the percentage abundances of each gas, multiply each gases abundance by their molar mass.
molar mass of air=28.02(.78)+32(.21)+39.95(.01) = 28.98 g/mol.
using two sig figs =29 g/mol
32.00 g O2
39.95 g Ar
Using the percentage abundances of each gas, multiply each gases abundance by their molar mass.
molar mass of air=28.02(.78)+32(.21)+39.95(.01) = 28.98 g/mol.
using two sig figs =29 g/mol
dry air 0% humidity is approximately 78% N2, 21% 02,1% Ar by moles. calculate thew molar massand density of dry air at 0% at 1atm?
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