Asked by Sharon
I did the math for the previous problem I posted, using this formula: -b+ or - the square root of b^2-4ac/2a. When I did this for -x^2+2x-1, I got 0/-2. I did the math and the x and y intercept came out to be -2 and -2. But when I graphed this on my graphic calculator, the points didn't cross through -2, and my answer sounds wrong. How can I fix this?
Answers
Answered by
bobpursley
a=-1 b=2 c=-1
b^2-4ac is zero
x=-1, double root. I don't know how you got zero and -2
b^2-4ac is zero
x=-1, double root. I don't know how you got zero and -2
Answered by
No name
by using the formula you should get
x1=x2=1
so your graph will be upside down porabola with y intercept at -1 so the graph will cut the y-axis at -1, and touch the x-axis at 1.
:)
x1=x2=1
so your graph will be upside down porabola with y intercept at -1 so the graph will cut the y-axis at -1, and touch the x-axis at 1.
:)
Answered by
Sharon
Thank you no name. :)
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