Question

In a reaction between methane, CH4+ and chlorine, Cl2+ four products can form: CH3Cl, CH2Cl2 + CHCl3+ and CCl4. In a particular instance, 20.8 g of CH4 were allowed to react with excess Cl2 and gave 5.0 g CH3Cl, 25.5 g CH2Cl2+ and 59.0 g CHCl3+ all the CH4 reacted.
a) How many grams of CCl4 were formed?
b) On the basis of available CH4+ what is the theoretical yield of CCl4?
c) What is the percentage yield of CCl4?
d) How many grams of Cl4 reacted with the CH4?

Answer 1

See your other post under Sunny.