Asked by Jon
Write y= -4x^2+8x-1 in vertex form.
y= (-4x^2+8x+2+16)-1+2+16
y= (-2x+4)^2+17 (answer)
y= (-4x^2+8x+2+16)-1+2+16
y= (-2x+4)^2+17 (answer)
Answers
Answered by
Reiny
no, the coefficient of the x term inside the bracket should be 1
so
y= -4x^2+8x-1
= -4[x^2 - 2x ] - 1
= -4[x^2 - 2x <b>+ 1 - 1</b>] - 1
= -4[(x-1)^2 - 1] - 1
= -4(x-1)^2 + 4 - 1
= -4(x-1)^2 + 3
so the vertex is (1,3)
so
y= -4x^2+8x-1
= -4[x^2 - 2x ] - 1
= -4[x^2 - 2x <b>+ 1 - 1</b>] - 1
= -4[(x-1)^2 - 1] - 1
= -4(x-1)^2 + 4 - 1
= -4(x-1)^2 + 3
so the vertex is (1,3)
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