Asked by Boo Boo
In each reaction, calculate the moles of product (in parentheses) when 3.00 moles of each reactant is used.
A: 4Li+O2 = 2Li2O (Li2O)
B: Fe2O3+3H2 = 2Fe+3H2O (Fe)
C: Al2S3+6H2O = 2Al(OH)3+3H2S (H2S)
Please show work, Thanks
A: 4Li+O2 = 2Li2O (Li2O)
B: Fe2O3+3H2 = 2Fe+3H2O (Fe)
C: Al2S3+6H2O = 2Al(OH)3+3H2S (H2S)
Please show work, Thanks
Answers
Answered by
bobpursley
a. if you have 3 moles of O2, 3 moles of Li, you are limited by the Li. You should get then the mole ratio of product to Li (2/4) times the moles of Li, or 2/4*3 moles Li2O
b. You will be limited by three moles of H2. You get then 2Fe, and 3H2o
c. you will be limited by the H2o, so you get 1 aluminum hydroxide, and 1.5 H2S moles
b. You will be limited by three moles of H2. You get then 2Fe, and 3H2o
c. you will be limited by the H2o, so you get 1 aluminum hydroxide, and 1.5 H2S moles
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