Question

why bond angle in cl2o is larger than h2o

Answer 1

The dipole for H2O is positive but with O the negative end and H the positive end. In Cl2O, the O is the positive end and Cl the negative end. That lets the lone pair on O (in Cl2)) move closer to the O atom and that provides more repulsive force for the "other" end. Thus the Cl2O angle is larger than the H2O angle. I tried to find a good web page but didn't.

Answer 2

because their are 3 lone pair on chlorine whereas no lone pair on hydrogen atom,,,, so their is higher repulsive force in chlorine and oxygen atoms than that of hydrogen....so due to this repulsion bond tends to stretch and high bond angle in cl2o.

Answer 3

Oxygen is more electronegative than chlorine. Then how come in Cl2O, oxygen became positive end?

Answer 4

Both chlorine and hydrogen have 2 lone pair of electron in Cl2O and H2O respectively.

Answer 5

This is due to sterric crowding...chlorine belongs to 3rd period therefore its atom is comparitively bulkier...besides the lone pairs present in chlorine atoms repel each other hence increasing the cl-o-cl bond

Answer 6

This is due to sterric crowding...chlorine belongs to 3rd period therefore its atom is comparitively bulkier...besides the lone pairs present on chlorine atoms repel each other hence increasing the cl-o-cl bond