Asked by Alexa
Calculate the volume of oxygen you would need, at 1.00 atm and 298 K, to completely oxidize 51g of glucose.
Answers
Answered by
DrBob222
Write and balance the equation.
C6H12O6 + 6O2 ==> 6CO2 + 6H2O
mols glucose = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols glucose to mols O2.
Now convert mols O2 to volume (L) using PV = nRT and the conditions listed.
C6H12O6 + 6O2 ==> 6CO2 + 6H2O
mols glucose = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols glucose to mols O2.
Now convert mols O2 to volume (L) using PV = nRT and the conditions listed.
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