Question

Two window washers, Bob and Joe, are on a 3.00-m-long, 335-N scaffold supported by two cables attached to its ends. Bob weighs 755 N and stands 1.00 m from the left end,Two meters from the left end is the 500-N washing equipment. Joe is 0.500 m from the right end and weighs 850 N. Given that the scaffold is in rotational and translational equilibrium, what are the forces on each cable?
a. left cable _________ kN
b. right cable _________kN

Answer 1

I will be happy to check your work. Also, do remember sum of vertical forces is zero.

Answer 2

Fy=0= T1+t2-755-335-500-850
Sum of tor. =0= (T2*3)-755(1)-335(2)-500(2)-850(2.5)
I solved for T1=923.34
and
T2=1516.666
But it's still wrong. I'm not sure what I am doing wrong