Question
A mass of 2.9 kg is hanging vertically from a string with a length of 2.4 meters. It is then raised to an angle of 50 degrees with the vertical and given some velocity, v. If the string breaks at a tension of 163.8 Newtons, what is the maximum value for v such that the string does not break. Answer in m/s.
Answers
Elena
mg=Tcosα
cosα=mg/T
PE=KE
PE= mgh=mgL(1-cosα)
KE= mv²/2
mv²/2=mgL(1-cosα)
v=sqrt{2gL(1-cos α)}= sqrt{2gL(1- mg/T)}=…
cosα=mg/T
PE=KE
PE= mgh=mgL(1-cosα)
KE= mv²/2
mv²/2=mgL(1-cosα)
v=sqrt{2gL(1-cos α)}= sqrt{2gL(1- mg/T)}=…