Asked by Chelsea
A mass of 2.9 kg is hanging vertically from a string with a length of 2.4 meters. It is then raised to an angle of 50 degrees with the vertical and given some velocity, v. If the string breaks at a tension of 163.8 Newtons, what is the maximum value for v such that the string does not break. Answer in m/s.
Answers
Answered by
Elena
mg=Tcosα
cosα=mg/T
PE=KE
PE= mgh=mgL(1-cosα)
KE= mv²/2
mv²/2=mgL(1-cosα)
v=sqrt{2gL(1-cos α)}= sqrt{2gL(1- mg/T)}=…
cosα=mg/T
PE=KE
PE= mgh=mgL(1-cosα)
KE= mv²/2
mv²/2=mgL(1-cosα)
v=sqrt{2gL(1-cos α)}= sqrt{2gL(1- mg/T)}=…
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.