Asked by Chelsea
An object of mass 26 kg is thrown straight upwards from the ground at 27 m/s. Due to air resistance (a non-conservative force), the object loses some of its initial energy during its trip to reach maximum height and only travels to a height above the ground of 16.3 meters. What percentage of its initial energy is lost to air resistance during its flight to maximum height?
Answers
Answered by
Elena
Without air resistance
KE=PE
mv²/2=mgh
h=v²/2g =27²/2•9.8 = 37.2 m
(mgh-mgh1)/mgh = (h-h1)/h= (37.2-16.3)/37.2=0.56
56%
KE=PE
mv²/2=mgh
h=v²/2g =27²/2•9.8 = 37.2 m
(mgh-mgh1)/mgh = (h-h1)/h= (37.2-16.3)/37.2=0.56
56%
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