as you know,
extrema where f'=0 and f''≠0
1.
f' = 6/7 x^(-1/7) is never zero
2.
f' = 24x^2 - 96x = 24x(x-4)
f'' = 48x
should be easy now to locate extrema
1. Find all relative extrema of the function f(x)=x^(6/7)-3. Use the Second Derivative Test where applicable.
2. Find all relative extrema of the function f(x)=2x^4-16x^3+4. Use the Second Derivative Test where applicable.
1 answer