Asked by Ezra
What is the zeff value for a valence electron in an oxygen atom?
An explanation would be much appreciated.
An explanation would be much appreciated.
Answers
Answered by
DrBob222
I found an answer with explanation on the web.
http://www.chemicalforums.com/index.php?topic=25187.0
http://www.chemicalforums.com/index.php?topic=25187.0
Answered by
Pragati Shalini
Electronic configuration of oxygen: 1s2 2s2 2p4
S= 0.35x6 + 0.85x2
= 2.1 + 1.7
= 3.8
Z eff = 8-3.8
= 4.2
S= 0.35x6 + 0.85x2
= 2.1 + 1.7
= 3.8
Z eff = 8-3.8
= 4.2
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