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Asked by Jake

explain why the equation x^(5)-3x+1=0 must have a solution with 0 < x <1
12 years ago

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Answered by Steve
Let f(x) = x^5 - 3x + 1

f(0) = 1
f(1) = -1

Since f is continuous on 0<=x<=1, it assumes all values between 1 and -1, which includes zero.
12 years ago
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explain why the equation x^(5)-3x+1=0 must have a solution with 0 < x <1

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