Asked by Rachel
A concave mirror is constructed so that a man at a distance of 19 cm from the mirror sees his image magnified 2.0 times. What is the radius of the curvature?
OK so I have tried to work this out and can't seem to find the answer. Here is what I got. Please let me know if you know what I am doing wrong?
m=2.0
do=19 cm
m=-di/do=hi/ho
m(do)=di
2.0(19)=di
di=-38
1/f=1/di+1/do
f=dodi/do-di
f=-12.7
f=r/2
r=-25
What am I doing wrong???
OK so I have tried to work this out and can't seem to find the answer. Here is what I got. Please let me know if you know what I am doing wrong?
m=2.0
do=19 cm
m=-di/do=hi/ho
m(do)=di
2.0(19)=di
di=-38
1/f=1/di+1/do
f=dodi/do-di
f=-12.7
f=r/2
r=-25
What am I doing wrong???
Answers
Answered by
bobpursley
As I remember, M should be - for virtual inverted images. If he sees his own image, it must be virtual, Check that convention,please.
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