Asked by EMM
An air mattress is 2.36 m long, 0.640 m wide, and 12.2 cm deep. If the air mattress itself has a mass of 0.252 kg, what is the maximum mass it can support in fresh water?
Answers
Answered by
Henry
Vm = 2.36 * 0.640 * 0.122 = 0.1843 m^3=
Vol. of the mattress.
Dw=(0.252+x)/0.1843=1000kg/m^3.=Density of water.
(0.252+x)/0.1843 = 1000.
0.252 + x = 184.3
X = 184.3 - 0.252 = 184.05 kg = max. mass it can support.
Vol. of the mattress.
Dw=(0.252+x)/0.1843=1000kg/m^3.=Density of water.
(0.252+x)/0.1843 = 1000.
0.252 + x = 184.3
X = 184.3 - 0.252 = 184.05 kg = max. mass it can support.
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