Asked by Melanie

An archer wishes to shoot an arrow at a target at eye level a distance of 45.0 m away. If the initial speed imparted to the arrow is 68.2 m/s, what angle should the arrow make with the horizontal as it is being shot?

Answers

Answered by Henry
Range = Vo^2*sin(2A)/g.

Range = 45 m.
Vo = 68.2 m/s.
g = 9.8 m/s^2.
Solve for angle A.
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