Asked by fat
A pound of body fat stores an amount of chemical energy equivalent to 3500 Cal (remember, 1 Calorie = 1 kilocalorie). When sleeping, the average adult burns or expends about 0.45 Cal/h for every pound of body weight. How long, in days, would the person have to sleep continuously to lose a pound of body fat?
Answers
Answered by
DrBob222
0.45 Cal/hr x 24 hr = 10.8 Cal/day.
10.8 Cal/day x ? day = 3500 = ?
Hello Rip Van Winkle.
10.8 Cal/day x ? day = 3500 = ?
Hello Rip Van Winkle.
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