In the figure below, block 1 of mass m1 = 3.0 kg and block 2 of mass m2 = 1.0 kg are connected by a string of negligible mass. Block 2 is pushed by force F of magnitude 30 N and angle θ = 20°. The coefficient of kinetic friction between each block and the horizontal surface is 0.25. What is the tension in the string?

and without a diagram....

file:///C:/Users/FAZI/Desktop/6-p-096.gif

To find the tension in the string, we need to consider the forces acting on the two blocks.

1. Calculate the horizontal force applied by block 2:
Fx = F * cos(θ)
Fx = 30 N * cos(20°)
Fx ≈ 28.64 N

2. Calculate the friction force acting on block 1:
Friction force = coefficient of kinetic friction * normal force
Normal force = weight of block 1 = m1 * g, where g is the acceleration due to gravity (approximately 9.8 m/s^2)
Friction force = 0.25 * (m1 * g)

3. Calculate the net force acting on block 1:
Net force = applied force - friction force
Net force = Fx - Friction force

4. Apply Newton's second law of motion to block 1:
Net force = m1 * acceleration
(Fx - Friction force) = m1 * acceleration

5. Calculate the acceleration of the system:
acceleration = (Fx - Friction force) / m1

6. Calculate the tension in the string:
tension in the string = m1 * acceleration + Friction force

You can plug in the given values to calculate the tension in the string.