Look at the table of 9s facts. Can you think of another number pattern in the multiples of 9? Explain

Yes. The digits always add up to 9.

9
18
27
36

and so on

The tens place in the product is in a pattern the pattern is 1,2,3,4,5,6,7,8 the ones place is the opposite the other pattern is 8,7,6,5,4,3,2,1

Yes. The factores add 9 every single time you multiply

Yes because,if you just turn the pattern over like this

9×8
9×7
9×6
And on so this is how to do another number pattern

Yes because,if you just turn the pattern it will be

0×9
1×9
And on so this is how to do a another number pattern.

I hate life y7che7ydhcrc7g7rgf

Yes the pattern in the tens is 1 2 3 4 5 6 7 8 the ones place is the opposite and the pattern is 8 7 6 5 4 3 2 1

12

100+100= 200

Yes, another number pattern that can be observed in the multiples of 9 is that the sum of the digits of each multiple of 9 is always divisible by 9.

To understand this pattern, let's look at an example. Let's take the first few multiples of 9: 9, 18, 27, 36, 45, and so on. If we look at the sum of the digits of each number:

9: 9
18: 1 + 8 = 9
27: 2 + 7 = 9
36: 3 + 6 = 9
45: 4 + 5 = 9

We can see that in each case, the sum of the digits is always 9. This pattern continues for all multiples of 9.

Now, let's understand why this pattern holds true. Every number can be expressed as the sum of its digits multiplied by appropriate powers of 10. For example, the number 45 can be written as (4 * 10) + (5 * 1).

Since 9 is a factor of 10 - 1, any multiple of 9 can be expressed as the sum of its digits multiplied by appropriate powers of 10 - 1. For example, 45 can be expressed as (4 * (10 - 1)) + (5 * (1 - 1)), which simplifies to (4 * 9) + (5 * 0).

Since any power of 0 is 0, the second term becomes 0. Therefore, any multiple of 9 can be written as (Sum of digits) * 9, which means the sum of the digits is always a factor of the multiple itself.

In conclusion, the pattern in the multiples of 9 is that the sum of the digits of each multiple is always divisible by 9.