Yes. The digits always add up to 9.
9
18
27
36
and so on
9
18
27
36
and so on
9×8
9×7
9×6
And on so this is how to do another number pattern
0×9
1×9
And on so this is how to do a another number pattern.
To understand this pattern, let's look at an example. Let's take the first few multiples of 9: 9, 18, 27, 36, 45, and so on. If we look at the sum of the digits of each number:
9: 9
18: 1 + 8 = 9
27: 2 + 7 = 9
36: 3 + 6 = 9
45: 4 + 5 = 9
We can see that in each case, the sum of the digits is always 9. This pattern continues for all multiples of 9.
Now, let's understand why this pattern holds true. Every number can be expressed as the sum of its digits multiplied by appropriate powers of 10. For example, the number 45 can be written as (4 * 10) + (5 * 1).
Since 9 is a factor of 10 - 1, any multiple of 9 can be expressed as the sum of its digits multiplied by appropriate powers of 10 - 1. For example, 45 can be expressed as (4 * (10 - 1)) + (5 * (1 - 1)), which simplifies to (4 * 9) + (5 * 0).
Since any power of 0 is 0, the second term becomes 0. Therefore, any multiple of 9 can be written as (Sum of digits) * 9, which means the sum of the digits is always a factor of the multiple itself.
In conclusion, the pattern in the multiples of 9 is that the sum of the digits of each multiple is always divisible by 9.