Asked by Anonymous
A 130 N block rests on a table. The suspended
mass has a weight of 63 N.
130 N
63 N
µs
a) What is the magnitude of the minimum
force of static friction required to hold both
blocks at rest?
Answer in units of N
mass has a weight of 63 N.
130 N
63 N
µs
a) What is the magnitude of the minimum
force of static friction required to hold both
blocks at rest?
Answer in units of N
Answers
Answered by
Elena
m1=130/9.8 kg , m2=63/9.8 =
m1•a=0=T-F(fr)
m2•a=0= m2g-T => T=m2•g
F(fr) =T =m2•g
m1•a=0=T-F(fr)
m2•a=0= m2g-T => T=m2•g
F(fr) =T =m2•g
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