Asked by Joe Joe
Jose left the airport and traveled toward the mountains. Kayla left 2.1 hours later traveling 35mph faster in an effort to catch up to him. After 1.2 hours Kayla finally caught up. Find Jose's average speed/
Answers
Answered by
Henry
Jose's speed = X mi/h.
Kayia's speed = (X+35)mi/h.
They had traveled the same distance:
Dj = Dk.
D=Xmi/h * (2.1+1.2)h=(X+35)mi/h * 1.2h.
3.3x = 1.2x + 42
2.1x = 42
X = 2o mi/h.
Kayia's speed = (X+35)mi/h.
They had traveled the same distance:
Dj = Dk.
D=Xmi/h * (2.1+1.2)h=(X+35)mi/h * 1.2h.
3.3x = 1.2x + 42
2.1x = 42
X = 2o mi/h.