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A stubborn, 120 {\rm kg} mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope a...Asked by joane
A stubborn, 191.0kg mule sits down and refuses to move. To drag the mule to the barn, the exasperated farmer ties a rope around the mule and pulls with his maximum force of 854.0N. The coefficients of friction between the mule and the ground are s=0.790 and k=0.280. What is the net force on the mule?
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Answered by
bobpursley
to start: net force=pulling-friction
= 854-191*g*.79
= 854-191*g*.79
Answered by
Oi
answer is 0
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