2 answers
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F=ILBsinα
sinα=1
B=F/IL = 2.2/2•1.5 =0.73 T
0.73 Tesla
6.60 Tesla
0.34 Tesla
0.61 Tesla
sinα=1
B=F/IL = 2.2/2•1.5 =0.73 T
The formula is given by:
F = BIL
Where:
F is the force experienced by the conductor (given as 2.2 N)
B is the magnetic field
I is the current flowing through the conductor (given as 1.5 A)
L is the length of the conductor (given as 2 m)
Rearrange the formula to solve for B:
B = F / (IL)
Substitute the given values into the formula:
B = 2.2 N / (1.5 A × 2 m)
B = 2.2 N / 3 A.m
B ≈ 0.73 Tesla
Therefore, the magnitude of the magnetic field that acts perpendicular to the flow of current in the conductor is approximately 0.73 Tesla.