(a) To find the final velocity, we can use the formula:
Final velocity = initial velocity + (acceleration × time)
Final velocity = 137 m/s + (23.1 m/s² × 20.0 s)
Final velocity = 137 m/s + 462 m/s
Final velocity = 599 m/s
The final velocity of the jet is 599 m/s.
(b) To find how many times the speed of sound the final speed is, we can divide the final speed by the speed of sound:
Number of times the speed of sound = final speed / speed of sound
Number of times the speed of sound = 599 m/s / 331 m/s
Number of times the speed of sound ≈ 1.81
The plane's final speed is approximately 1.81 times the speed of sound.
A supersonic jet flying at 137 m/s is accelerated uniformly at the rate of 23.1 m/s2 for 20.0 s.
(a) What is its final velocity?
(b) The speed of sound in air is 331 m/s. How many times the speed of sound is the plane's final speed?
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