Question

Not for homework, just practice problems I'm having trouble with.

Knowing that one mole of KHP, C8H5O4K, reacts with one mole of NaOH, what mass of KHP is required to neutralize 30.0 mL of the 0.10 M NaOH solution?

if 24.5 mL of the 0.10 M NaOH solution is required to reach the endpoint in a titration with an unknown monoprotic acid, how many moles of the acid were present?

Answer 1

Okay, I think i understand the second question.

moles=MxV
so...
moles=(24.5ml)(0.10M NaOH) = 2.45 moles
??