Asked by Fleur
                An electric kettle operates at 110V. What is the resistance of the kettle if the power is 1.5kW?
 
		
8.1 Ω
 		
1.4 Ω
 		
81 Ω
 		
14 Ω
I'm stuck between A and B
            
        8.1 Ω
1.4 Ω
81 Ω
14 Ω
I'm stuck between A and B
Answers
                    Answered by
            Damon
            
    v = i r so i = v/r
P = i v = i^2 r = v^2/r
1500 = 110^2/r
r = 8.07 Ohms
    
P = i v = i^2 r = v^2/r
1500 = 110^2/r
r = 8.07 Ohms
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.