Calculate the theoretical yield in moles of Fe(C5H7O2)3 for this experiment. Record this number on your data sheet.

Question

Calculate the theoretical yield in g Fe(C5H7O2)3 (GMM: 353.18g mol^-1), for this experiment. Record this number on your data sheet.

I really need help on these two questions. I have no idea on how to do it. Please somebody help me to solve these problems.

Answer 1

I don't know the equation and I have no idea what C5H7O2 is; however, on a best guess I can write an abbreviated equation as
Fe^3+ + 3C5H10O2==> Fe(C6H7O2)3
a. You provided no data; therefore, I can't calculate a theoretical yield. Again, my best guess is you have grams Fe or grams of the other component.
mols theoretical yield = (1/3)*mols C5H?O2 component. If it's Fe you have, then mols theoretical yield = same as mols Fe.

b. grams = mols x molar mass. You have mols fropm part a and you have molar mass in the problem. Solve away.