Asked by C0C0

A 60 kg box is on a 80 m long plane which is inclined at 30 degrees, the coefficient of friction is 0.25. How much force is needed to move it up a plane A.) at a constant velocity and B.) with an acceleration of 2 m/s^2

Answers

Answered by bobpursley
net force=m*a

net force up the plane: pushing force-weight down-friction
= F+mgSinTheta-mu*mg*cosTheta

so figure out F, given a=0, or a=2
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