Asked by HanuPhysics

A force of 50 N accelerates a 5.0 kg block at 6.0 m/s2 along a horizontal surface.

(a) What is the frictional force acting on the block?
(b) What is the coefficient of friction?
Answered by Elena
(a)ma=F-F(fr)
F(fr)= F-ma
(b) F(fr) =μmg
μ=F(fr)/mg