For y= 2x squared + x - 1 the x-intercepts and the turning point respectively are?

Answer 1

y = 2x^2 + x - 1
= (2x-1)(x+1)
that shows the x-intercepts

y = 2(x^2 + x/2) - 1
now add and subtract 2/16
y = 2(x^2 + x/2 + 1/16) -1 - 2/16
y = 2(x+1/4)^2 - 9/8
(y+9/8) = 2(x+1/4)^2
that shows where the vertex is. Note that x= -1/4 is halfway between the roots of -1 and 1/2