Asked by Liang
calculate the moles of indicated product produced when 26.0g of each reactant is used.
A. 4Al+3O2---->2AlO3 (Al2O3
B. 3NO2+H2O--->2HNO3+NO (HNO3)
A. 4Al+3O2---->2AlO3 (Al2O3
B. 3NO2+H2O--->2HNO3+NO (HNO3)
Answers
Answered by
DrBob222
These are limiting reagent problems; I know that because amounts are given for BOTH reactants.
Convert 26 g Al to mols. mols = grams/molar mass.
Do the same for 26 g O2.
Using the coefficients in the balanced equation, convert mols Al to mols Al2O3.
Do the same with mols O2 to mols Al2O3.
It is quite likely that the two values for mols Al2O3 will not be the same which means one of them is wrong; the correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Then convert the smaller value to grams. g = mols Al2O3 x molar mass Al2O3.
Convert 26 g Al to mols. mols = grams/molar mass.
Do the same for 26 g O2.
Using the coefficients in the balanced equation, convert mols Al to mols Al2O3.
Do the same with mols O2 to mols Al2O3.
It is quite likely that the two values for mols Al2O3 will not be the same which means one of them is wrong; the correct value in limiting reagent problems is ALWAYS the smaller value and the reagent producing that value is the limiting reagent.
Then convert the smaller value to grams. g = mols Al2O3 x molar mass Al2O3.
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