Question
On earth, two parts of a space probe weigh 18300 N and 4440 N. These parts are separated by a center-to-center distance of 5.11 m and may be treated as uniform spherical objects. Find the magnitude of the gravitational force that each part exerts on the other out in space, far from any other objects.
Answers
Steve
F = GmM/r^2
= G(w/g)(W/g) / r^2
= 6.673*10^-11 * (18300/9.8) * (440/9.8) / 5.11^2
= 2.14*10^-7 N
= G(w/g)(W/g) / r^2
= 6.673*10^-11 * (18300/9.8) * (440/9.8) / 5.11^2
= 2.14*10^-7 N
Steve
oops. missed a 4
6.673*10^-11 * (18300/9.8) * (4440/9.8) / 5.11^2= 2.16*10^-6 N
6.673*10^-11 * (18300/9.8) * (4440/9.8) / 5.11^2= 2.16*10^-6 N
Orla
Thank you for the answer, I probably should have specified that I only wanted a formula to help me figure it out, but thanks :)