F = GmM/r^2
= G(w/g)(W/g) / r^2
= 6.673*10^-11 * (18300/9.8) * (440/9.8) / 5.11^2
= 2.14*10^-7 N
On earth, two parts of a space probe weigh 18300 N and 4440 N. These parts are separated by a center-to-center distance of 5.11 m and may be treated as uniform spherical objects. Find the magnitude of the gravitational force that each part exerts on the other out in space, far from any other objects.
3 answers
oops. missed a 4
6.673*10^-11 * (18300/9.8) * (4440/9.8) / 5.11^2= 2.16*10^-6 N
6.673*10^-11 * (18300/9.8) * (4440/9.8) / 5.11^2= 2.16*10^-6 N
Thank you for the answer, I probably should have specified that I only wanted a formula to help me figure it out, but thanks :)
1 answer