Asked by bridget
how much work is done by the system when 2.00 moles of O2 expand from a volume of 3.00 liters to a volume of 5.8 liters against a constant external pressure of 0.0100 atm? answer in units of J
Answers
Answered by
DrBob222
work = -p*delta V
work = -0.01 atm*((5.8-3.00), then convert L*atm work to J.
1 L*atm = 101.325 J.
work = -0.01 atm*((5.8-3.00), then convert L*atm work to J.
1 L*atm = 101.325 J.
Answered by
IHateDrBob222
@sarah
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