Asked by anon
gotta find the first and second derivative of f(x)=x^2/(x-1)
thanks for help!
thanks for help!
Answers
Answered by
Steve
quotient rule:
f' = ((2x)(x-1) - (x^2)(1))/(x-1)^2
= x(x-2)/(x-1)^2
f'' = 2/(x-1)^3
Or, divide first:
f = x^2/(x-1) = x+1 + 1/(x-1)
f' = 1 - 1/(x-1)^2
f'' = 2/(x-1)^3
f' = ((2x)(x-1) - (x^2)(1))/(x-1)^2
= x(x-2)/(x-1)^2
f'' = 2/(x-1)^3
Or, divide first:
f = x^2/(x-1) = x+1 + 1/(x-1)
f' = 1 - 1/(x-1)^2
f'' = 2/(x-1)^3
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