Asked by Angela
A 0.17 kg baseball moving at +20.80 m/s is slowed to a stop by a catcher who exerts a constant force of -376 N.
How long does it take this force to stop the ball?
How far does the ball travel before stopping?
How long does it take this force to stop the ball?
How far does the ball travel before stopping?
Answers
Answered by
drwls
Force*Time = Initial Momentum = M*V
Time = (0.17)*(20.8)/376 = 9.4*10^-3 s
(Initial velocity)/2 * Time
= Stopping Distance
= 10.40*9.4*10^-3 = 0.0978 m
= 9.7 cm
Time = (0.17)*(20.8)/376 = 9.4*10^-3 s
(Initial velocity)/2 * Time
= Stopping Distance
= 10.40*9.4*10^-3 = 0.0978 m
= 9.7 cm
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