Asked by Angela

A 0.17 kg baseball moving at +20.80 m/s is slowed to a stop by a catcher who exerts a constant force of -376 N.
How long does it take this force to stop the ball?
How far does the ball travel before stopping?

Answers

Answered by drwls
Force*Time = Initial Momentum = M*V
Time = (0.17)*(20.8)/376 = 9.4*10^-3 s

(Initial velocity)/2 * Time
= Stopping Distance

= 10.40*9.4*10^-3 = 0.0978 m
= 9.7 cm
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