Asked by koko
A 1.16 kg block and a 2.32 kg block are initially at rest on a frictionless, horizontal surface, with a compressed spring of negligible mass between them. When the blocks are released, they move off in opposite directions. If the final velocity of the 1.16 kg block is 3.20 m/s to the left, what is the final velocity of the 2.32 kg block?
a.) Find Magnitude
b.) How much does the kinetic energy of the system increase?
a.) Find Magnitude
b.) How much does the kinetic energy of the system increase?
Answers
Answered by
Elena
0=m1•v1+m2•v2
v2= - m1•v1/v2= - 1.16•3.2/2.32 =1.6 m/s.
KE1=0
KE2=m1•v1²/2 +m2•v2²/2 =...
ΔKE=KE2-KE1=KE2
v2= - m1•v1/v2= - 1.16•3.2/2.32 =1.6 m/s.
KE1=0
KE2=m1•v1²/2 +m2•v2²/2 =...
ΔKE=KE2-KE1=KE2
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