Asked by aliceallyx3
How much HCl 9in grams) is needed to prepare 546 mL of solution with a pOH of 10.00 at 25?
Answers
Answered by
DrBob222
pOH = 10 means pH = 4 from
pH + pOH = pKw = 14.
pH = 4 = -log(H^+).
Solve for (H^+) = 1E-4 M
You want how many mols? That's 1E-4 mols/L x 0.546 L = ?
Then mol HCl = grams HCl/molar mass HCl.
You know mols and molar mass, solve for grams HCl.
pH + pOH = pKw = 14.
pH = 4 = -log(H^+).
Solve for (H^+) = 1E-4 M
You want how many mols? That's 1E-4 mols/L x 0.546 L = ?
Then mol HCl = grams HCl/molar mass HCl.
You know mols and molar mass, solve for grams HCl.
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