Asked by rory

A 62.0 kg diver falls from rest into a swimming pool from a height of 3.50 m. It takes 1.92 s for the diver to stop after entering the water. Find the magnitude of the average force exerted on the diver during that time.
Answered by DanH
First, calculate the velocity when he hits the water using:

V(f)^2 = V(o)^2 + 2as

Then, calculate the deceleration as he goes through the water using:

V(f) = V(o) + at.

Then you can get the force once you know a with F = ma.
Answered by rory
they want us to use the height somehow.
Answered by DanH
yes, in my first equation, the "s" is distance, or in this case, height.
Answered by rory
yeah its still not working i did that i think it wants us to more of an kinetic energy or work method to solve for it.
Answered by DanH
OK, you can do it that way. First, he has potential energy = mgh. This gets converted into kinetic energy. The kinetic energy when he hits the water is (mv^2)/2, so you can calculate his velocity when he hits the water. Then calculate his deceleration, and the force.
Answered by rory
thanks!
Answered by DanH
you're welcome!
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