Two-point form of linear equation :
y - y1 = ( y2 - y1 ) * ( x - x1 ) / ( x2 - x1 )
Add y1 to both sides
y - y1 + y1 = ( y2 - y1 ) * ( x - x1 ) / ( x2 - x1 ) + y1
y = ( y2 - y1 ) * ( x - x1 ) / ( x2 - x1 ) + y1
Alope-intercept form of linear equation :
y = m x + b
In this case :
x1 = 2
y1 = y
x2 = 3
y2 = 3
m = ( y2 - y1 ) / ( x2 - x1 ) = 2
( 3 - y ) / ( 3 - 2 ) = 2
( 3 - y ) / 1 = 2
3 - y = 2 Subtract 2 to both sides
3 - y - 2 = 2 - 2
1 - y = 0 Add y to both sides
1 - y + y = 0 + y
1 = y
y = 1
Can you please help me understand this? Thanks
Find the value of y so that the passing line through the two points has the given slope.
1. (2,y) (3,3) ;m=2
2 answers
just find the slope for the two points, set it equal to 2
(y-3)/(2-3) = 2 --- (y-3)/-1 = 2
y-3 = -2
y = 1
(y-3)/(2-3) = 2 --- (y-3)/-1 = 2
y-3 = -2
y = 1