Question
Weight of the mustard package Sample: 3.02 (g)
Weight of the mustard package Solution: 33.3 (g)
Trial #1 Trial #2 Trial #3
Weight of Mustard Package Solution Delivered (g) : 1.09 .948 .909
Weight of NaOH Solution Delivered (g) : .354 .304 .269
Concentration of NaOH : 7.48e-3 (g of NaOH/g of solution)
Calculate the weight percent of Mustard in your originally prepared solution.
Answers
Den
Forget it i got the answer
DrBob222
What are you titrating?
Den
mustard solution, how would i calculate the mass of naOH used?
DrBob222
mols NaOH used is M x L = ?mols NaOH used.
g NaOH used = mols x molar mass NaOH.
g NaOH used = mols x molar mass NaOH.
Den
After getting this, in order to convert the three masses into moles, what do I divide each mass by
DrBob222
The molar mass of what ever it is you are converting to mols. Which harks back to my original question of what are you titrating. The NaOH surely is titrating an acid; therefore, I expect you want grams of the acid. So mols of NaOH = M x L. Most of acid probably = mols NaOH (I assume a 1:1 reaction).
mol acid x molar mass acid = grams.
grams x the dilution factor converts g in the original sample to grams of the titrated sample.
%acid = (g acid/mass sample)*100 = ?
mols = grams/molar mass.
mol acid x molar mass acid = grams.
grams x the dilution factor converts g in the original sample to grams of the titrated sample.
%acid = (g acid/mass sample)*100 = ?
mols = grams/molar mass.