Question

You are pulling a 60-kg crate across a level floor with a rope. If a force of 200 N
on the rope gives the crate an acceleration of 2 m/s2, what is the force of friction
that the crate exerts on the floor?

Answer 1

ma=F-F(fr)
F(fr)=F+ma = 200 +60•2 =320 N