Asked by Beatris
The ACE towing company tows a disabled 10,500 N automobile off the road at a constant speed. If the tow line makes an angle of 10.0° with the vertical as shown, what is the tension in the line supporting the car?
Answers
Answered by
Elena
T•cosα=m•g
T=mg/cosα =
=10500/cos10°= 10660 N
T=mg/cosα =
=10500/cos10°= 10660 N
Answered by
Ivanna Pizz Budly
10,448 N
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