Asked by Anonymous
farmer jane has only pigs and chickens o her farm. she can't remembr how many of each she has but she does know she counted 110 legs and 35 heads. assuming that each animal is normalhow many of each animal does she have
Answers
Answered by
Steve
assuming 2 legs per animal, 35 heads would require 70 legs.
Given that there are 110 legs, that means an extra 40 legs, or 20 pairs.
So, there are 20 pigs and 15 chickens
algebraically,
p+c=35
4p+2c=110
p=20
c=15
Given that there are 110 legs, that means an extra 40 legs, or 20 pairs.
So, there are 20 pigs and 15 chickens
algebraically,
p+c=35
4p+2c=110
p=20
c=15
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